Optimal. Leaf size=37 \[ \frac {\text {Li}_2\left (1-\frac {a (1-c)+b (1+c) x}{a+b x}\right )}{2 a b} \]
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Rubi [A]
time = 0.02, antiderivative size = 37, normalized size of antiderivative = 1.00, number of steps
used = 1, number of rules used = 1, integrand size = 38, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.026, Rules used = {2497}
\begin {gather*} \frac {\text {PolyLog}\left (2,1-\frac {a (1-c)+b (c+1) x}{a+b x}\right )}{2 a b} \end {gather*}
Antiderivative was successfully verified.
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Rule 2497
Rubi steps
\begin {align*} \int \frac {\log \left (\frac {a (1-c)+b (1+c) x}{a+b x}\right )}{a^2-b^2 x^2} \, dx &=\frac {\text {Li}_2\left (1-\frac {a (1-c)+b (1+c) x}{a+b x}\right )}{2 a b}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(252\) vs. \(2(37)=74\).
time = 0.13, size = 252, normalized size = 6.81 \begin {gather*} \frac {\log ^2\left (\frac {2 a c}{(1+c) (a+b x)}\right )-2 \log (a-b x) \log \left (\frac {a+b x}{2 a}\right )+2 \log (a-b x) \log \left (\frac {a-a c+b (1+c) x}{2 a}\right )+2 \log \left (\frac {2 a c}{(1+c) (a+b x)}\right ) \log \left (-\frac {a-a c+b (1+c) x}{2 a c}\right )-2 \log (a-b x) \log \left (\frac {a-a c+b (1+c) x}{a+b x}\right )-2 \log \left (\frac {2 a c}{(1+c) (a+b x)}\right ) \log \left (\frac {a-a c+b (1+c) x}{a+b x}\right )-2 \text {Li}_2\left (\frac {a-b x}{2 a}\right )+2 \text {Li}_2\left (\frac {(1+c) (a-b x)}{2 a}\right )-2 \text {Li}_2\left (\frac {(1+c) (a+b x)}{2 a c}\right )}{4 a b} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.78, size = 24, normalized size = 0.65
method | result | size |
derivativedivides | \(\frac {\dilog \left (1+c -\frac {2 c a}{b x +a}\right )}{2 b a}\) | \(24\) |
default | \(\frac {\dilog \left (1+c -\frac {2 c a}{b x +a}\right )}{2 b a}\) | \(24\) |
risch | \(\frac {\dilog \left (1+c -\frac {2 c a}{b x +a}\right )}{2 b a}\) | \(24\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 246 vs.
\(2 (33) = 66\).
time = 0.31, size = 246, normalized size = 6.65 \begin {gather*} \frac {1}{2} \, {\left (\frac {\log \left (b x + a\right )}{a b} - \frac {\log \left (b x - a\right )}{a b}\right )} \log \left (\frac {b {\left (c + 1\right )} x - a {\left (c - 1\right )}}{b x + a}\right ) + \frac {\log \left (b x + a\right )^{2} - 2 \, \log \left (b x + a\right ) \log \left (b x - a\right )}{4 \, a b} + \frac {\log \left (b x - a\right ) \log \left (\frac {b {\left (c + 1\right )} x - a {\left (c + 1\right )}}{2 \, a} + 1\right ) + {\rm Li}_2\left (-\frac {b {\left (c + 1\right )} x - a {\left (c + 1\right )}}{2 \, a}\right )}{2 \, a b} + \frac {\log \left (b x + a\right ) \log \left (-\frac {b x + a}{2 \, a} + 1\right ) + {\rm Li}_2\left (\frac {b x + a}{2 \, a}\right )}{2 \, a b} - \frac {\log \left (b x + a\right ) \log \left (-\frac {b {\left (c + 1\right )} x + a {\left (c + 1\right )}}{2 \, a c} + 1\right ) + {\rm Li}_2\left (\frac {b {\left (c + 1\right )} x + a {\left (c + 1\right )}}{2 \, a c}\right )}{2 \, a b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.35, size = 34, normalized size = 0.92 \begin {gather*} \frac {{\rm Li}_2\left (\frac {a c - {\left (b c + b\right )} x - a}{b x + a} + 1\right )}{2 \, a b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.03 \begin {gather*} \int \frac {\ln \left (-\frac {a\,\left (c-1\right )-b\,x\,\left (c+1\right )}{a+b\,x}\right )}{a^2-b^2\,x^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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